Solving Inequalities In R: A Step-by-Step Guide
Hey guys! Today, we're diving into the world of inequalities and how to solve them using the power of R. We'll break down each problem step-by-step, making sure even if you're new to this, you'll get the hang of it. Let's get started! Inequalities are mathematical statements that compare two expressions using symbols like '<' (less than), '>' (greater than), 'β€' (less than or equal to), and 'β₯' (greater than or equal to). Solving an inequality means finding all the values of the variable (usually 'x') that make the inequality true. The main difference between solving equations and inequalities is that when you multiply or divide both sides of an inequality by a negative number, you have to flip the inequality sign. Keep this in mind as we tackle each problem. So, grab your notebooks and let's solve some inequalities in R!
a) Solving 2β10x < -8β15
Alright, let's kick things off with the first inequality: 2β10x < -8β15. Our goal here is to isolate 'x'. Here's how we do it, piece by piece. First, let's get rid of the coefficient of 'x', which is 2β10
. To do this, we'll divide both sides of the inequality by 2β10
. Now, let's actually perform the division. Dividing both sides by 2β10
gives us:
x < (-8β15) / (2β10)
Now, let's simplify the right-hand side. We can simplify the fraction by dividing both the numerator and the denominator by 2:
x < (-4β15) / β10
Next, let's rationalize the denominator by multiplying the numerator and denominator by β10:
x < (-4β15 * β10) / (β10 * β10)
Which simplifies to:
x < (-4β150) / 10
We can further simplify the square root of 150 because it contains a perfect square: β150 = β(25 * 6) = 5β6
. Letβs substitute it back:
x < (-4 * 5β6) / 10
x < (-20β6) / 10
Finally:
x < -2β6
So, the solution to the inequality is x < -2β6
. This means any value of 'x' that is less than -2β6
will satisfy the original inequality. To get a numerical approximation for the solution, we can calculate the value of -2β6
, which is approximately -4.898. Therefore, x must be less than -4.898.
b) Solution steps unavailable
This problem's solution steps were not provided in the original request. We will proceed to the next available problem.
c) Solving -4β7x > -8β21
Let's solve -4β7x > -8β21. To isolate 'x', we'll divide both sides by -4β7
. Remember, when we divide or multiply an inequality by a negative number, we flip the inequality sign! Here's what that looks like: Dividing both sides by -4β7
and flipping the sign we get:
x < (-8β21) / (-4β7)
Next, let's simplify the right side of the inequality. First, divide both numerator and denominator by -4:
x < (2β21) / β7
Now, we can simplify the fraction further by dividing β21
by β7
:
x < 2β(21/7)
x < 2β3
So, the solution to this inequality is x < 2β3
. This means any value of 'x' that is less than 2β3
will satisfy the original inequality. The approximate value of 2β3
is 3.464. Therefore x must be less than 3.464.
d) Solving -3β12x β₯ 12β15
Now, let's tackle -3β12x β₯ 12β15. To isolate 'x', we'll divide both sides by -3β12
. Again, remember that when we divide by a negative number, we flip the inequality sign! Hereβs how it goes: dividing both sides by -3β12
gives us:
x β€ (12β15) / (-3β12)
Next, let's simplify the right-hand side. Divide 12 by -3:
x β€ (-4β15) / β12
Now, let's simplify the square root of 12, since β12 = β(4 * 3) = 2β3
. Substituting that into the equation:
x β€ (-4β15) / (2β3)
Simplify by dividing -4 and 2:
x β€ (-2β15) / β3
Now, let's rationalize the denominator by multiplying the numerator and denominator by β3:
x β€ (-2β15 * β3) / (β3 * β3)
Which simplifies to:
x β€ (-2β45) / 3
We can simplify the square root of 45: β45 = β(9 * 5) = 3β5
. Let's substitute that in:
x β€ (-2 * 3β5) / 3
x β€ (-6β5) / 3
Finally:
x β€ -2β5
So, the solution to the inequality is x β€ -2β5
. This means any value of 'x' that is less than or equal to -2β5
will satisfy the original inequality. The approximate value of -2β5
is -4.472. Thus, x must be less than or equal to -4.472.
e) Solving -12β40 < 24β2x
Alright, letβs work through -12β40 < 24β2x. To isolate 'x', we need to divide both sides by 24β2
. The inequality sign remains the same in this case, as we're dividing by a positive number. Hereβs the breakdown: dividing both sides by 24β2
:
(-12β40) / (24β2) < x
Now, let's simplify the left side of the inequality. First, simplify the fraction by dividing -12 by 24:
(-β40) / (2β2) < x
We can simplify the square root of 40: β40 = β(4 * 10) = 2β10
. Let's substitute that in:
(-2β10) / (2β2) < x
Simplify by dividing 2 by 2:
-β10 / β2 < x
Letβs rationalize the denominator:
(-β10 * β2) / (β2 * β2) < x
This simplifies to:
-β20 / 2 < x
We can simplify the square root of 20: β20 = β(4 * 5) = 2β5
. Substituting it back in:
(-2β5) / 2 < x
Finally:
-β5 < x
So, the solution to this inequality is x > -β5
. This means any value of 'x' that is greater than -β5
will satisfy the original inequality. The approximate value of -β5
is -2.236. So, x must be greater than -2.236.
f) Solving -2β45 > -3β10x
Last but not least, let's solve -2β45 > -3β10x. To isolate 'x', we'll divide both sides by -3β10
. Remember, since we are dividing by a negative number, we have to flip the inequality sign! Hereβs how it goes:
x < (-2β45) / (-3β10)
Let's simplify the right-hand side. The negative signs cancel each other out:
x < (2β45) / (3β10)
We can simplify the square root of 45: β45 = β(9 * 5) = 3β5
. Substituting:
x < (2 * 3β5) / (3β10)
x < (6β5) / (3β10)
Divide 6 by 3:
x < (2β5) / β10
Now, letβs rationalize the denominator by multiplying the numerator and denominator by β10:
x < (2β5 * β10) / (β10 * β10)
This simplifies to:
x < (2β50) / 10
Simplify the square root of 50: β50 = β(25 * 2) = 5β2
. Substitute it in:
x < (2 * 5β2) / 10
x < (10β2) / 10
Finally:
x < β2
So, the solution to this inequality is x < β2
. This means any value of 'x' that is less than β2
will satisfy the original inequality. The approximate value of β2
is 1.414. Therefore, x must be less than 1.414.
And that's it, guys! We have successfully solved all the inequalities. Remember to always pay attention to the inequality sign and flip it when multiplying or dividing by a negative number. Keep practicing, and you'll become a pro in no time. If you want, solve the same problems using a calculator and check each result. Happy solving!