Solving For X And Y: A Math Problem Explained

by TextBrain Team 46 views

Hey guys! Let's dive into a math problem that might look a little intimidating at first glance, but trust me, it's totally manageable. We're going to break down the equation 2832=2xy\sqrt{2\sqrt{8}\sqrt{32}} = 2\frac{x}{y} and figure out what the values of x and y are. This kind of problem is a great way to practice your understanding of radicals and exponents. So, grab a pen and paper, and let's get started! This is more than just finding a solution; it's about understanding the why behind each step. We will begin by simplifying the radical expression on the left side of the equation, step by step, making sure that we don't miss anything. This process will involve understanding the properties of square roots and the ability to simplify radical expressions. It’s like peeling back the layers of an onion to get to the juicy core. The core of the problem involves manipulating the terms under the square root to find common factors and reduce the expression to its simplest form.

First things first, let's focus on simplifying the expression under the main square root. We have 2832\sqrt{2\sqrt{8}\sqrt{32}}. Our goal is to simplify the radicals within this expression. The trick is to recognize that both 8 and 32 can be expressed as powers of 2. This allows us to simplify the expression using the properties of square roots and exponents. It is a common mathematical technique to look for numbers that can be expressed as powers of the same base, which simplifies the calculations. This also aligns with the general goal of simplifying expressions to make them easier to work with. Remember, the goal here is not to just get to the answer, but to understand the process. In essence, this is about finding the most simplified form of a radical expression. This is often the key to solving problems involving radicals, as it transforms complex expressions into something more manageable. This strategy will simplify our expression into a more easily solvable form. The ability to rewrite radicals in simpler forms is a fundamental skill in mathematics. So, let's get started. Let's tackle the innermost square roots first.

Breaking Down the Radicals

Okay, guys, let's break this down step by step. We have 8\sqrt{8} and 32\sqrt{32}. Let's simplify these. Remember that 8\sqrt{8} can be written as 4Γ—2\sqrt{4 \times 2}, and since 4=2\sqrt{4} = 2, we get 222\sqrt{2}. Similarly, 32\sqrt{32} can be written as 16Γ—2\sqrt{16 \times 2}, and since 16=4\sqrt{16} = 4, we get 424\sqrt{2}. See, not so bad, right? Now our original equation 2832=2xy\sqrt{2\sqrt{8}\sqrt{32}} = 2\frac{x}{y} becomes 2Γ—22Γ—42=2xy\sqrt{2 \times 2\sqrt{2} \times 4\sqrt{2}} = 2\frac{x}{y}. Isn't it easier to look at? This is exactly what mathematical simplification is about; breaking down complex things into smaller, more understandable parts. The simplification process is crucial because it allows us to see the underlying structure of the mathematical expressions and identify opportunities to solve equations more easily. This is a step-by-step process, and by simplifying the radicals, we are making our equation much easier to solve. Always remember that practice makes perfect when simplifying radicals. This helps you become more efficient in solving such problems. So, are you ready to simplify even further? Let's multiply those numbers together! We will then evaluate the expression to obtain a cleaner expression. This will further simplify the problem and allow for easy solving.

Now, we'll continue our journey by substituting the simplified radicals back into the original equation and see how things transform. When we substitute 222\sqrt{2} for 8\sqrt{8} and 424\sqrt{2} for 32\sqrt{32} into the original equation, we get 2Γ—22Γ—42\sqrt{2 \times 2\sqrt{2} \times 4\sqrt{2}}. Let's multiply the numbers first: 2Γ—2Γ—4=162 \times 2 \times 4 = 16. Now we have 16Γ—2Γ—216 \times \sqrt{2} \times \sqrt{2}. Recall that 2Γ—2=2\sqrt{2} \times \sqrt{2} = 2. So, our expression becomes 16Γ—2=3216 \times 2 = 32. Amazing, right? The expression under the main square root has now become a simple number, making our original equation much easier to solve. Now the left side of our equation 2832=2xy\sqrt{2\sqrt{8}\sqrt{32}} = 2\frac{x}{y} has turned into 32=2xy\sqrt{32} = 2\frac{x}{y}. It's like the problem is starting to unfold itself! We can now focus on simplifying the final square root. This is an important step, so pay close attention! Also, always remember that simplifying radicals involves rewriting the expression in the simplest form possible. This simplifies the entire process, providing a clear path towards the solution. So, are you ready for the next phase?

Final Simplification and Solving for x and y

Alright, we're in the home stretch, guys! We've simplified our equation to 32=2xy\sqrt{32} = 2\frac{x}{y}. Now, we need to simplify 32\sqrt{32}. We know that 32=16Γ—232 = 16 \times 2, and 16=4\sqrt{16} = 4, so 32=42\sqrt{32} = 4\sqrt{2}. This gives us 42=2xy4\sqrt{2} = 2\frac{x}{y}. Now, to solve for xy\frac{x}{y}, we divide both sides of the equation by 2, giving us 22=xy2\sqrt{2} = \frac{x}{y}. Now, here comes the tricky part. Notice that we have 2\sqrt{2} in the equation, but the answer choices are all whole numbers. This means we're probably looking for a way to rewrite our equation. If we rewrite 222\sqrt{2} into a form xy\frac{x}{y}, and if xx is the whole number and yy is 11, we can safely assume that 222\sqrt{2} can be approximately represented as 2Γ—1.4141=2.8281\frac{2\times 1.414}{1} = \frac{2.828}{1}. The question is slightly flawed. The ideal format for this question would have been to use the approximate values of square root to determine the appropriate values, but given the options available, you will probably get an answer closer to an approximate value. Also, given our knowledge of the equation format, this is impossible to be solved as it is. So, to adjust the equation, we can rewrite our equation into 2832=42=2xy\sqrt{2\sqrt{8}\sqrt{32}} = 4\sqrt{2} = 2\frac{x}{y}. Dividing both sides by 22, we get 22=xy2\sqrt{2} = \frac{x}{y}. Now, let's look at our options, and let's assume that we approximate 2\sqrt{2} with a value of 11. Then we can say that, xx equals approximately 22 and yy equals approximately 11. Unfortunately, the given answer options do not give us enough information to solve this problem. However, given the problem's context, we can solve it approximately by dividing the sides by 22, giving us 22=xy2\sqrt{2} = \frac{x}{y}. Multiplying both sides with the approximate value of 2\sqrt{2}, which is 1.41.4, we get x=2.8x = 2.8, and y=1y = 1. However, given the options, there is no way for us to determine the appropriate answer.

Unfortunately, there seems to be an issue with the given options, as the correct solution doesn't align with the provided choices. If we were to solve the equation accurately, the presence of 2\sqrt{2} would mean that xx and yy wouldn't be whole numbers. If the question intended us to approximate or interpret the final value, it may be difficult to solve. Therefore, given the choices provided, it is impossible to determine a final answer. If we were to determine the value of xx and yy, then it will be dependent on the accuracy we are willing to provide.

However, given the nature of the question, and with some reasonable approximations, the most likely answer would be one that gets closest to the ratio we have derived. This shows how important it is to understand the underlying concepts and apply logical reasoning even when the options aren't ideal. Always remember to double-check your work and make sure your answers make sense within the context of the problem. The important thing is to understand the process and what we did. So, keep practicing, and you'll become a pro at solving these kinds of problems in no time!