Factoring Polynomials: $-12x^4y^5 + 6x^6y^2$ Explained

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Hey guys! Let's dive into factoring a polynomial today. We're going to break down the expression βˆ’12x4y5+6x6y2-12x^4y^5 + 6x^6y^2, especially when we know one of its factors is (2y3βˆ’x2)(2y^3 - x^2). Factoring polynomials can seem tricky at first, but with a clear approach, it becomes much more manageable. We'll explore the steps involved, making sure you understand each part of the process. So, let’s get started and make polynomial factoring a breeze!

Understanding the Basics of Factoring

Before we jump into the specifics of our problem, let's quickly recap what factoring is all about. Factoring is essentially the reverse of multiplying. When we factor a polynomial, we're trying to break it down into simpler expressions that, when multiplied together, give us the original polynomial. Think of it like this: if you have the number 12, you can factor it into 3 times 4 (3 * 4 = 12). With polynomials, we’re doing the same thing but with algebraic expressions.

To effectively factor, it's crucial to identify common factors within the terms. A common factor is something that divides evenly into all terms of the polynomial. This could be a number, a variable, or even a more complex expression. Spotting these common factors is the first big step in simplifying the polynomial. Once you identify and factor out the common terms, the remaining expression often becomes easier to work with. This initial step sets the stage for further factoring, if needed, and ultimately helps in simplifying complex algebraic expressions. Recognizing and extracting common factors is a fundamental skill in algebra, and it's key to mastering polynomial manipulation.

Identifying Common Factors

Identifying the common factors in a polynomial is the first crucial step in the factoring process. Guys, this involves looking at both the coefficients (the numbers in front of the variables) and the variables themselves. Let’s consider our polynomial, βˆ’12x4y5+6x6y2-12x^4y^5 + 6x^6y^2. First, we look at the coefficients: -12 and 6. What’s the greatest common divisor (GCD) of these numbers? The GCD is the largest number that divides evenly into both. In this case, it's 6. So, 6 will be part of our common factor.

Next, we turn our attention to the variables. We have x4x^4 and x6x^6. The common factor here will be the lowest power of x that appears in both terms, which is x4x^4. Similarly, for the y terms, we have y5y^5 and y2y^2. The common factor is y2y^2, as it's the lowest power of y present in both terms. Putting it all together, the greatest common factor (GCF) for the entire polynomial is 6x4y26x^4y^2. Factoring out this GCF will significantly simplify the expression, making it easier to handle and allowing us to proceed with further factoring steps if necessary. This initial identification of common factors is a cornerstone technique in polynomial simplification and is vital for solving more complex algebraic problems.

Factoring out the Greatest Common Factor (GCF)

Now that we've identified the GCF as 6x4y26x^4y^2, let's factor it out from our polynomial, βˆ’12x4y5+6x6y2-12x^4y^5 + 6x^6y^2. To do this, we'll divide each term in the polynomial by the GCF. When we divide βˆ’12x4y5-12x^4y^5 by 6x4y26x^4y^2, we get βˆ’2y3-2y^3. Remember, when dividing terms with exponents, we subtract the exponents of like variables. So, x4x^4 divided by x4x^4 is 1 (they cancel out), and y5y^5 divided by y2y^2 is y5βˆ’2=y3y^{5-2} = y^3. The -12 divided by 6 gives us -2.

Next, we divide 6x6y26x^6y^2 by 6x4y26x^4y^2. Here, 6 divided by 6 is 1, x6x^6 divided by x4x^4 is x6βˆ’4=x2x^{6-4} = x^2, and y2y^2 divided by y2y^2 is 1 (they cancel out). So, this term simplifies to x2x^2. Now, we can rewrite the original polynomial by factoring out the GCF: 6x4y2(βˆ’2y3+x2)6x^4y^2(-2y^3 + x^2). This means we've expressed our polynomial as the product of the GCF and the remaining expression inside the parentheses. Factoring out the GCF is a crucial step in simplifying polynomials, as it often reveals further factoring opportunities and makes the expression easier to work with. This technique is fundamental in algebra and is used extensively in solving equations and simplifying more complex expressions.

Incorporating the Given Factor

The problem gives us a specific factor, (2y3βˆ’x2)(2y^3 - x^2), and asks us to factor the polynomial considering this. Notice anything familiar? Look back at the expression we obtained after factoring out the GCF: 6x4y2(βˆ’2y3+x2)6x^4y^2(-2y^3 + x^2). The term inside the parentheses, (βˆ’2y3+x2)(-2y^3 + x^2), looks quite similar to our given factor, (2y3βˆ’x2)(2y^3 - x^2). They have the same terms but with opposite signs. This is a key observation.

To make them match exactly, we can factor out a -1 from the term (βˆ’2y3+x2)(-2y^3 + x^2). This changes the signs inside the parentheses, giving us βˆ’1(2y3βˆ’x2)-1(2y^3 - x^2). Now, substituting this back into our expression, we get 6x4y2βˆ—βˆ’1(2y3βˆ’x2)6x^4y^2 * -1(2y^3 - x^2), which simplifies to βˆ’6x4y2(2y3βˆ’x2)-6x^4y^2(2y^3 - x^2). Voila! We've now factored the polynomial in a way that explicitly includes the given factor. Recognizing these kinds of relationships and knowing how to manipulate signs is a crucial skill in factoring. It allows us to align our factored expressions with given factors, making the factoring process more targeted and efficient. This step demonstrates how a keen eye for detail and an understanding of algebraic manipulation can lead to a solution.

Rewriting and Final Factoring

After factoring out the GCF and manipulating the signs, we've arrived at the expression βˆ’6x4y2(2y3βˆ’x2)-6x^4y^2(2y^3 - x^2). This form clearly shows the given factor, (2y3βˆ’x2)(2y^3 - x^2), as part of the factored polynomial. So, the final factored form of our original polynomial, βˆ’12x4y5+6x6y2-12x^4y^5 + 6x^6y^2, considering the given factor, is indeed βˆ’6x4y2(2y3βˆ’x2)-6x^4y^2(2y^3 - x^2). This completes the factoring process.

The key here was not just identifying and factoring out the GCF but also recognizing the relationship between the remaining terms and the given factor. By strategically factoring out a -1, we were able to match the signs and reveal the desired factor. Guys, this process highlights the importance of careful observation and algebraic manipulation in factoring problems. It’s a testament to how understanding the underlying principles of algebra can help simplify complex expressions and arrive at the solution. This final factored form is not only a simplified representation of the original polynomial but also explicitly includes the factor we were asked to consider.

Conclusion

So, guys, we've successfully factored the polynomial βˆ’12x4y5+6x6y2-12x^4y^5 + 6x^6y^2 considering the factor (2y3βˆ’x2)(2y^3 - x^2). We started by identifying the greatest common factor (GCF), which was 6x4y26x^4y^2. We factored this out, simplified the expression, and then cleverly manipulated the signs to match the given factor. This involved recognizing that (βˆ’2y3+x2)(-2y^3 + x^2) is the negative of (2y3βˆ’x2)(2y^3 - x^2), which allowed us to factor out a -1 and align the terms.

The final factored form, βˆ’6x4y2(2y3βˆ’x2)-6x^4y^2(2y^3 - x^2), clearly showcases the given factor. This exercise demonstrates the power of strategic factoring and how understanding the relationships between terms can lead to a solution. Factoring polynomials might seem daunting at first, but by breaking it down into manageable stepsβ€”identifying common factors, factoring them out, and then looking for further simplifications or given factorsβ€”it becomes a much more approachable task. Keep practicing these techniques, and you'll become a factoring pro in no time! Remember, the key is to be systematic and observant, and soon you'll be tackling even the most complex polynomials with confidence.