Evaluating Radical Expressions: A Step-by-Step Guide

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Hey guys! Today, we're diving into the fascinating world of radical expressions. You know, those expressions with the cool-looking root symbols? We're going to break down how to evaluate them, step by step. This guide will specifically focus on simplifying expressions involving the multiplication of radicals with the same index. So, grab your pencils and let's get started!

Understanding the Basics of Radical Expressions

Before we jump into the examples, let's quickly recap the basics. A radical expression consists of a radical symbol (√), an index (the small number above the radical symbol, indicating the type of root), and a radicand (the number or expression under the radical symbol). For instance, in the expression an\sqrt[n]{a}, 'n' is the index and 'a' is the radicand. When 'n' is not explicitly written (like in a\sqrt{a}), it's understood to be 2, representing the square root.

The key concept we'll be using here is the product rule for radicals. This rule states that if you have two radicals with the same index, you can multiply them by multiplying the radicands together under a single radical with that same index. Mathematically, it looks like this: anβ‹…bn=aβ‹…bn\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{a \cdot b}. This rule is our superpower for simplifying these expressions!

Why is this rule so important? Well, it allows us to combine separate radicals into one, often making it easier to simplify the radicand and find the root. Think of it like merging two smaller piles of ingredients into one larger pile to make the cooking process more efficient. Now that we've got the theory down, let's tackle some examples to see this rule in action. Remember, the goal is to simplify each expression as much as possible, so we'll be looking for opportunities to factor and extract perfect powers from the radicands.

Problem 1: 165β‹…25\sqrt[5]{16} \cdot \sqrt[5]{2}

Let's kick things off with our first expression: 165β‹…25\sqrt[5]{16} \cdot \sqrt[5]{2}. The most important thing to notice here is that both radicals have the same index, which is 5. This means we can directly apply the product rule we just discussed. So, we combine the radicands under a single fifth root: 16β‹…25\sqrt[5]{16 \cdot 2}.

Now, let's simplify the radicand. 16 multiplied by 2 equals 32, so our expression becomes 325\sqrt[5]{32}. Great! We're one step closer to the solution. But can we simplify this further? Absolutely! We need to think: is 32 a perfect fifth power? In other words, is there a number that, when raised to the power of 5, gives us 32?

The answer is yes! We know that 25=2β‹…2β‹…2β‹…2β‹…2=322^5 = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 32. So, 32 is indeed a perfect fifth power. Therefore, we can rewrite our expression as 255\sqrt[5]{2^5}. The fifth root and the fifth power essentially cancel each other out, leaving us with our final simplified answer: 2.

So, to recap, we used the product rule to combine the radicals, simplified the radicand, and then recognized the perfect fifth power to arrive at the solution. This is the general strategy we'll be using for the other problems as well. Remember to always look for opportunities to simplify the radicand after applying the product rule. Sometimes, you'll find perfect squares, cubes, or other powers hiding inside, just waiting to be extracted!

Problem 2: 100006β‹…1006\sqrt[6]{10000} \cdot \sqrt[6]{100}

Alright, let's move on to our second problem: 100006β‹…1006\sqrt[6]{10000} \cdot \sqrt[6]{100}. Just like before, the key observation is that both radicals have the same index, which is 6 in this case. This allows us to use the product rule for radicals. Remember that rule? anβ‹…bn=aβ‹…bn\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{a \cdot b}. Let's apply it!

Combining the radicands under a single sixth root, we get 10000β‹…1006\sqrt[6]{10000 \cdot 100}. Now, let's simplify the radicand. 10000 multiplied by 100 equals 1,000,000. So, our expression becomes 10000006\sqrt[6]{1000000}. Okay, this looks like a big number, but don't be intimidated! We can handle this.

The next step is to figure out if 1,000,000 is a perfect sixth power. This means we need to find a number that, when raised to the power of 6, equals 1,000,000. A good strategy here is to try expressing 1,000,000 as a power of 10. We know that 1,000,000 has six zeros, which means it can be written as 10610^6. See? It wasn't so scary after all!

Now we can rewrite our expression as 1066\sqrt[6]{10^6}. Just like in the previous problem, the sixth root and the sixth power cancel each other out, leaving us with the simplified answer: 10. Awesome! We've successfully simplified another radical expression.

This problem highlights the importance of recognizing powers of common numbers like 10. Breaking down large numbers into their prime factors or recognizing them as powers of 10 can make simplification much easier. Remember to always look for these patterns when dealing with radicals!

Problem 3: 0.1083β‹…23\sqrt[3]{0.108} \cdot \sqrt[3]{2}

Now let's tackle a problem with decimals: 0.1083β‹…23\sqrt[3]{0.108} \cdot \sqrt[3]{2}. Don't let the decimal scare you! The process is still the same. The first thing we notice is that both radicals are cube roots (index of 3). This means we can confidently apply the product rule for radicals. So, we combine the radicands under a single cube root: 0.108β‹…23\sqrt[3]{0.108 \cdot 2}.

Next, we need to simplify the radicand. 0. 108 multiplied by 2 equals 0.216. So, our expression becomes 0.2163\sqrt[3]{0.216}. Now, this is where things might seem a little trickier because we're dealing with a decimal. But we can handle it!

To figure out if 0.216 is a perfect cube, it can be helpful to think about it as a fraction. 0.216 can be written as 216/1000. So, our expression now looks like 21610003\sqrt[3]{\frac{216}{1000}}. Now we have a fraction under the cube root, which we can further simplify by taking the cube root of the numerator and the cube root of the denominator separately. This gives us 216310003\frac{\sqrt[3]{216}}{\sqrt[3]{1000}}.

Now, let's think about the cube roots of 216 and 1000. Do we know any numbers that, when cubed, give us these values? Well, 63=6β‹…6β‹…6=2166^3 = 6 \cdot 6 \cdot 6 = 216 and 103=10β‹…10β‹…10=100010^3 = 10 \cdot 10 \cdot 10 = 1000. Perfect! This means 2163=6\sqrt[3]{216} = 6 and 10003=10\sqrt[3]{1000} = 10.

Substituting these values back into our expression, we get 610\frac{6}{10}, which can be simplified to 35\frac{3}{5} or 0.6. So, the simplified form of our original expression is 0.6. Excellent work!

This problem demonstrates how converting decimals to fractions can be a useful strategy when dealing with radicals. It allows us to work with whole numbers and potentially identify perfect cubes (or other powers) more easily. Remember to always look for ways to rewrite the expression in a more manageable form.

Problem 4: 35β‹…528β‹…33β‹…568\sqrt[8]{3^5 \cdot 5^2} \cdot \sqrt[8]{3^3 \cdot 5^6}

Let's move on to our final problem, which looks a bit more complex: 35β‹…528β‹…33β‹…568\sqrt[8]{3^5 \cdot 5^2} \cdot \sqrt[8]{3^3 \cdot 5^6}. But don't worry, we'll break it down just like the others. As always, the first thing to notice is that both radicals have the same index, which is 8. This means we can use the product rule. Let's combine those radicands under a single eighth root: (35β‹…52)β‹…(33β‹…56)8\sqrt[8]{(3^5 \cdot 5^2) \cdot (3^3 \cdot 5^6)}.

Now, we need to simplify the expression inside the radical. We have products of powers with the same base. Remember the rule for multiplying exponents with the same base? We add the exponents! So, 35β‹…33=35+3=383^5 \cdot 3^3 = 3^{5+3} = 3^8 and 52β‹…56=52+6=585^2 \cdot 5^6 = 5^{2+6} = 5^8.

Our expression now looks like 38β‹…588\sqrt[8]{3^8 \cdot 5^8}. Notice anything special? We have both 3 and 5 raised to the power of 8! This is great news because we're taking the eighth root. We can rewrite this as (3β‹…5)88\sqrt[8]{(3 \cdot 5)^8} using the power of a product rule. 3 times 5 is 15, so we have 1588\sqrt[8]{15^8}.

And now, the moment we've been waiting for! The eighth root and the eighth power cancel each other out, leaving us with our simplified answer: 15. Fantastic! We've successfully navigated a more complex-looking radical expression.

This problem highlights the importance of understanding and applying the rules of exponents when simplifying radical expressions. Recognizing patterns like products of powers with the same base can make the simplification process much smoother. Always keep those exponent rules in the back of your mind!

Conclusion

So, there you have it! We've worked through four different examples of evaluating radical expressions involving multiplication. We've seen how the product rule for radicals allows us to combine radicals with the same index, and we've explored strategies for simplifying radicands, including recognizing perfect powers, converting decimals to fractions, and applying the rules of exponents.

The key takeaway here is that simplifying radical expressions is all about breaking down the problem into smaller, more manageable steps. Look for opportunities to apply the product rule, simplify the radicand, and recognize patterns that can help you find the solution. With practice, you'll become a pro at evaluating radical expressions. Keep practicing, and you'll be simplifying radicals like a boss in no time! Remember, math can be fun, especially when you start to see the patterns and connections. Keep exploring, keep learning, and keep simplifying!